seriously? again? xD
*sigh, looks like i have to work on my code again xD
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You got me this time. Have to go out now.
I'll solve it later
Out of time to solve the 3rd puzzle.
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Bump ! it was pretty hard and also nice puzzle for me. thanks :)
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people already solved it, but I got a solution where I got one number in two different threes (so 6 remaining)
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Solution:
- 4+139+146 = 83+102+104 = 90+98+101 = 289. Leftover characters: xXJhs
- 5+107+193 = 49+73+183 = 70+112+123 = 305. Leftover characters: aUiYa
Both giveaways stated that for the third giveaway you need numbers 101 4 193 107 70. The trick was to find characters corresponding to these numbers on the puzzle diagrams. You didn't even had to solve them to find that:
- From the first puzzle:
101 => O,4 => m,70 => s. - From the second puzzle:
193 => 9,107 => V,70 => s.
Knowing this, numbers 101 4 193 107 70 could be translated to Om0Vs.
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If you liked my previous puzzle, here's more.
Two puzzles. Three giveaways. Solve puzzles to find the 3rd giveaway.
Also check out my other digits puzzle.
Puzzle has ended. Solution is posted here.
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