Puzzle for Everspace 2 - ends May 6th 8PM CEST

Oh, thank you!

Seems like an intriguing workaround.
Not that I intend to WIN this game since I own the first one, but it's a nice exercise when I'm out of college.

I don't think talking about this should be an issue now that the puzzle has ended. I also tried to get Chat GPT to solve the problem. It is not just a simple chat bot, it will look up how to solve the equations you give it so it can solve your problem.

I used Chat GPT through Bing since I think that is supposed to be the newest version. I heard something about Wolfram Alpha being integrated into Chat GPT so it can do more advanced math, but I'm not sure if that was something Chat GPT was adding for everyone or if it was just someone experimenting with adding it.

The chat bot seemed like it knew what it was doing, but didn't get the answer correct. I don't know where it went wrong because I don't know how to do the math. I don't know if it just got the math wrong or if I didn't give it the correct equation because I couldn't type it into the text box in the same way it was provided.

This technology is progressing very fast and this is definitely going to take over how we search the internet for information very soon.

Me: I am going to launch something vertically. I am trying to figure out what altitude the object will reach at 60 seconds and what the peak g force the object will experience is. The object will be launched from 0 meters. I have a vertical velocity profile that says the objects velocity in meters/second for t=[0,60] seconds is going to be: -1/50t3+9/5t2

Chat bot: To calculate the altitude and peak g force of an object launched vertically, we need to use the following equations:

Altitude: The altitude of an object launched vertically can be calculated using the following equation 1:

h = v0t + 1/2at^2

where h is the altitude, v0 is the initial velocity (in this case 0), t is the time elapsed (in this case 60 seconds), and a is the acceleration due to gravity (9.8 m/s2).

Using your velocity profile equation:

v(t) = -1/50t^3 + 9/5t^2

We can integrate it to get the position function:

h(t) = -1/600t^4 + 3/10t^3

Plugging in t=60 seconds, we get:

h(60) = -1/600(60)^4 + 3/10(60)^3 = 10800 meters

Peak g force: The peak g force experienced by an object launched vertically can be calculated using the following equation 2:

gmax = sqrt(a^2 + (dv/dt)^2) / g

where a is the acceleration due to gravity (9.8 m/s2), dv/dt is the derivative of velocity with respect to time, and g is the acceleration due to gravity.

Using your velocity profile equation:

v(t) = -1/50t^3 + 9/5t^2

We can differentiate it to get the acceleration function:

a(t) = -3/50t^2 + 18/5t

Plugging in t=30 seconds (halfway point), we get:

a(30) = -3/50(30)^2 + 18/5(30) = 35.28 m/s2

Plugging in a and dv/dt into the equation above, we get:

gmax = sqrt((9.8 m/s2)2 + (35.28 m/s2)2) / (9.8 m/s^2) ≈ 4.6 g

I hope this helps! Let me know if you have any other questions.

Me: Can you calculate the peak g force to the 5th decimal place?

Chat bot: Sure! The peak g force experienced by the object launched vertically is approximately 4.60433 g.

heh, no luck, but thx for trying :)