Description

A key from Indiegala's Halloween Scratchy Sale
I hope you'll enjoy the game!

By the way, how do I find x for which is sum of floor(((x+n-1)/n)^(1/1989)) for n=1 to 1989 equal to 1990?

I dunno, man...^(1/1989))=1990, when n is 1 to 1989) Too many parentheses!
New link.

6 years ago*
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I did try Wolfram (sum floor(((x+n-1)/n)^(1/1989)) for n=1 to 1989) but it did not really help.

6 years ago
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Oh wow, I realize now how far I've sunk since my school days..uj.

6 years ago
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New link. Doesn't tell me much either.

6 years ago
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Oh well. Thanks anyway!

6 years ago
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Thanks for the Giveaway much Appreciated : )

6 years ago
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I have no idea! Thank you for the giveaway, though!

6 years ago
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Gracias

6 years ago
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Thank you...

6 years ago
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Thanks for the chance

6 years ago
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Thanks a lot.

6 years ago
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Enjoy!

6 years ago
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