A key from Indiegala's Halloween Scratchy Sale
I hope you'll enjoy the game!
By the way, how do I find x for which is sum of floor(((x+n-1)/n)^(1/1989)) for n=1 to 1989 equal to 1990?
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I dunno, man...^(1/1989))=1990, when n is 1 to 1989)Too many parentheses!New link.
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I did try Wolfram (sum floor(((x+n-1)/n)^(1/1989)) for n=1 to 1989) but it did not really help.
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Oh wow, I realize now how far I've sunk since my school days..uj.
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New link. Doesn't tell me much either.
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Oh well. Thanks anyway!
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Thanks for the Giveaway much Appreciated : )
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I have no idea! Thank you for the giveaway, though!
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Gracias
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Thank you...
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Thanks for the chance
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Thanks a lot.
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Enjoy!
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