40 + 5 = 45 then 45 : 5 = 9 then 9 - 5 = 4 then 4 x 5 = 20.
Starting from the number 40, we performed the following operations: add 5, diVide by 5, subtract 5 and muLtiply by 5. At the end of the
chain, we have reached the number 20.
Always starting from 40 and performing these 4
operations, but in a different order, what is
the larGest number that can be obtained at
end of the chain?
40 + 5 = 45 then 45 : 5 = 9 then 9 - 5 = 4 then 4 x 5 = 20.
Starting from the number 40, we performed the following operations: add 5, diVide by 5, subtract 5 and muLtiply by 5. At the end of the
chain, we have reached the number 20.
Always starting from 40 and performing these 4
operations, but in a different order, what is
the larGest number that can be obtained at
end of the chain?
Comment has been collapsed.